Determine if 25110 is divisible by 45

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WebJun 4, 2024 · determine if 25110 is divisible by 45. (Hint:- 5 and 9 are co-prime numbers. test the divisibility of the number by 5 and 9). - 18057840 WebWe know that if a number ' a ' is divisible by another number ' b ', then it is divisible by each of the factors of that number ' b '. Now the factors of 45 are 5 and 9, where 5 and 9 are co-prime to each other. In order to test the divisibility of 25110 by 45 we will have to check the divisibility of this number by both 9 and 5.

Determine if 25110 is divisible by 45 [Hint: 5 and 9 are co-prime ...

WebDetermine if 25110 is divisible by 45. Solution: 45 = 5 x 9 Here, 5 and 9 are co-prime numbers. Test of divisibility by 5: unit place of the given number 25110 is 0. So, it is divisible by 5. Test of divisibility by 9: Sum of the digits = 2 + 5 + l + l + 0 = 9 which is divisible by 9. So, yes the given number is divisible by 5 and 9 both. WebDetermine if 25110 is divisible by 45. According to the divisibility rule of 45 if the last digit of a number is divisible by 5 and the sum of the digits is divisible by 9, then the number is divisible by 45. 45 = 5 × 9. Factors of 5 = 1 and 5. Factors of 9 = 1, 3 and 9. Therefore, 5 and 9 are co-prime numbers, howard center mental health first aid

Ex 3.5, 10 - Determine if 25110 is divisible by 45 - teachoo

WebJul 20, 2024 · Question From - NCERT Maths Class 6 Chapter 3 EXERCISE 3.5 Question – 10 PLAYING WITH NUMBERS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-Determine if … Web45 = 5×9. Factors of 5 = 1,5. Factors of 9 = 1.3,9. Therefore, 5 and 9 are co-prime numbers. Since the last digit of 25110 is 0. It is divisible by 5. Sum of the digits of 25110 = 2+5+1+1+0= 9. As the sum of the digits of 25110 is divisible by 9, therefore, 25110 is divisible by 9. Since the number is divisible by 5 and 9 both, it is divisible ... Web45 = 5×9. Factors of 5 = 1,5. Factors of 9 = 1.3,9. Therefore, 5 and 9 are co-prime numbers. Since the last digit of 25110 is 0. It is divisible by 5. Sum of the digits of 25110 = … howard center for women waycross ga

Determine if 25110 is divisible by 45 Hint 5 and 9 - Tutorix

Question 10 Determine if 25110 is divisible by 45. [Hint: 5 and 9 …

WebDetermine if 25110 is divisible by 45. Medium. Open in App. Solution. Verified by Toppr. Given number 2 5 1 1 0. It need to be divisile by both 5, 9 to make sure that it is divisible by 4 5. Since the unit digit is 0 it is divisible by 5. The sum of digits is 2 + 5 + 1 + 1 + 0 = 9 so it is divisible by 9. howard center staff accessWebJul 20, 2024 · Question From - NCERT Maths Class 6 Chapter 3 EXERCISE 3.5 Question – 10 PLAYING WITH NUMBERS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION … howard center jesup ga

"WebDetermine if 25110 is divisible by 45. [Hint: 5 and 9 are co-prime numbers. Test the divisibility of the number by 5 and 9]. Answer : 45 = 5 x 9. Here, 5 and 9 are co-prime numbers. unit place of the given number is 0. So, it is divisible by 5. Sum of the digits = 2 + 5 + l + l + 0 = 9 which is divisible by 9. " - Determine if 25110 is divisible by 45

Determine if 25110 is divisible by 45

WebJul 18, 2024 · As we know factors of 45 = 3×3×5 So, if 25110 is divisible by , it must be divisible by all factors of 45 also , So factors of 45 are (3,3,5). We will check the divisibility of 25110 by 3 and 5 . Divisibility of 25110 by 3 if a number is divisible by 3 then sum of digits of that number must be divisible by 3. 2+5+1+1+0 = 9 ⇒ 25510 is ... WebJul 15, 2024 · Answer:Yes: 558Step-by-step explanation: 25110 ÷ 45 = 558. HYDRADYNAMO HYDRADYNAMO 07/15/2024 Mathematics College answered …

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Web45 = 5 × 9. 1, 5 are factors of 5. 1, 3, 9 are factors of 9. Hence, 5 and 9 are co-prime numbers. The last digit of 25110 is 0. Hence, it is divisible by 5. Sum of digits 25110. 2 … WebDetermine if 25110 is divisible by 45. Medium. Open in App. Solution. Verified by Toppr. Given number 2 5 1 1 0. It need to be divisile by both 5, 9 to make sure that it is divisible …

Web45 = 5 × 9. Factors of 5 = 1, 5. Factors of 9 = 1, 3, 9. Therefore, 5 and 9 are co-prime numbers. Since the last digit of 25110 is 0, it is divisible by 5. Sum of the digits of 25110 = 2 + 5 + 1 + 1 + 0 = 9. As the sum of the digits of 25110 is … WebMar 11, 2024 · Hint: In this particular type of question divisibility of 25110 by 45 can be checked by checking the divisibility with the co prime factors of 45 using common divisibility rules of the factors. Complete step-by-step answer: Prime factors of 45 = 5 × 3 × 3. Thus 5 and 9 are co-primes and if 25110 is divisible by 5 and 9 then it would be ...

WebHere we have 25110, the unit's digit is 0. So, it is divisible by 5. The condition for divisibility by 9: Sum of the digits of a number should be a multiple of 9. For 25110, the sum of the … WebOct 10, 2024 · We have to find whether 25110 is divisible by 45. Solution: Factors of 5 are 1 and 5. Factors of 9 are 1, 3 and 9. This implies, 5 and 9 are co-prime numbers. …

WebJul 19, 2024 · Answer: 25110 is divisible by 5. Step-by-step explanation: In order to test the divisibility of 25110 by 45 we will have to check the divisibility of this number by both 9 and 5. Sum of digits of 25110 is 2 + 5 + 1 + 1 + 0 = 9, which is divisible by 9. Moreover, since the last digit of this number is zero, this number is also divisible by 5.

WebSo, 45 = 5 × 9. Let's check if 25110 is divisible by 5. Since, 25110 has 0 as its unit digit therefore, 25110 is divisible by 5 (If a number has 0 or 5 as it's unit digit the, the number is divisible by 5) Now, let's check if 25110 is divisible by 9. Let's find the sum of the digits. … howard center for women\u0027s health tifton gaWebDetermine if 25110 is divisible by 45. [Hint: 5 and 9 are co-prime numbers. Test the divisibility of the number by 5 and 9]. Answer : 45 = 5 x 9. Here, 5 and 9 are co-prime … how many immigrants entered the us in 2019WebAnswers (1) 45 = 5 9. Factors of 5 = 1, 5. Factors of 9 = 1. 3, 9. Therefore, 5 and 9 are co-prime numbers. Since the last digit of 25110 is 0. it is divisible by 5. Sum of the digits of … howard center st albansWeb> Determine if 25110 is divis... maths. Determine if 25110 is divisible by 45. Medium. Answer. Given number 2 5 1 1 0. It need to be divisile by both 5, 9 to make sure that it is divisible by 4 5. Since the unit digit is 0 it is divisible by 5. The sum of digits is 2 + 5 + 1 + 1 + 0 = 9 so it is divisible by 9. howard center matWebJun 24, 2024 · 25110 is divisible be 45 and the answer is 558 . as per checking the divisibility of the 25110 by 5 and 9 so the divisibility rule of 5 says that the unit digit should be 0 or 5 and this number satisfy this and the divisibility rule of 9 says that the sum of all the digits in the number should be divisible by 9, so by adding 2,5,1,1,0 the answer is 9 and … howard center steingardWebQuestion 10. Determine if 25110 is divisible by 45. [Hint: 5 and 9 are co-prime numbers. Test the divisibility of the number by 5 and 9]. howard center in covington gaWeb45 = 5 × 9. 1, 5 are factors of 5. 1, 3, 9 are factors of 9. Hence, 5 and 9 are co-prime numbers. The last digit of 25110 is 0. Hence, it is divisible by 5. Sum of digits 25110. 2 + 5 + 1 + 1 + 0 = 9. Since, the sum of digits of 25110 is divisible by 9. Hence, 25110 is divisible by 9. Since the number is divisible by both 5 and 9. Therefore ... how many immigrants enter legally each year